nLab
continuum

Contents

Idea

A continuum is in general something opposite to a discrete. There are several notions of continuum in mathematics:

In physics one may also mean by a continuum a medium which spreads the physical quantities spatially with some finite density, unlike the physics of a system of particles, where an infinite (delta-distribution-like) density is attached to a discrete system of points. See at geometry of physics for more on the relation of the continuum in form of the real line to physics.

In cohesive homotopy type theory

One can axiomatize aspects of the notion of line continuum in cohesive homotopy type theory. There the idea of an object 𝔸 1\mathbb{A}^1 all whose points are, while different, connectable by continuous paths (and uniquely so, up to suitable homotopy) is encoded in asking that after applying the fundamental ∞-groupoid functor Π\mathbf{\Pi} to it, the result is something contractible

Π(𝔸 1)*. \mathbf{\Pi}(\mathbb{A}^1) \simeq * \,.
Example

In the model of cohesive homotopy type theory called Smooth∞Grpd we have a full and faithful embedding of smooth manifolds. Therefore we can embed the integers \mathbb{Z}, the rational numbers \mathbb{Q} as well as the real numbers \mathbb{R}, all equipped with their canonical smooth manifold structure. This is discrete for the first two, but not for the last one, and homotopy cohesion can detect this:

Π(); \mathbf{\Pi}(\mathbb{Z}) \simeq \mathbb{Z} \,;
Π(); \mathbf{\Pi}(\mathbb{Q}) \simeq \mathbb{Q} \,;

but

Π()*. \mathbf{\Pi}(\mathbb{R}) \simeq * \,.

This reflects the fact that the points of \mathbb{R} form a continuum, but those of \mathbb{Z} and \mathbb{Q} do not.

Also the complex numbers \mathbb{C} with their canonical manifold structure of course form a continuum in this sense

Π()*. \mathbf{\Pi}(\mathbb{C}) \simeq * \,.
Proposition

For a ring object 𝔸 1\mathbb{A}^1 to be geometrically contractible, Π(𝔸 1)*\Pi(\mathbb{A}^1) \simeq *, it is sufficient that there be a map ii from a bipointed type (left,right,I)(left, right, I) to the bipointed type (0,1,𝔸 1)(0, 1, \mathbb{A}^1) such that II is geometrically contractible.

Hence in words: “If in the ring 𝔸 1\mathbb{A}^1 the elements 0 and 1 are path-connected, then 𝔸 1\mathbb{A}^1 is already contractible, hence is a line continuum.”

Proof

Under the given assumptions we obtain a commuting diagram of the form

𝔸 0 I×𝔸 1 mult(i,id) 𝔸 1 id 𝔸 1. \array{ \mathbb{A} \\ \downarrow & \searrow^{\mathrlap{ 0}} \\ I \times \mathbb{A}^1 &\stackrel{ mult\circ (i,id)}{\to}& \mathbb{A}^1 \\ \uparrow & \nearrow_{\mathrlap{id}} \\ \mathbb{A}^1 } \,.

Since Π\Pi preserves products, it sends this to a diagram of the form

0 Π(𝔸 1) Π(𝔸 1) id, \array{ & \nearrow \searrow^{\mathrlap{0}} \\ \Pi(\mathbb{A}^1) &\Downarrow_{\simeq}& \Pi(\mathbb{A}^1) \\ & \searrow \nearrow_{\mathrlap{id}} } \,,

which exhibits a contracting homotopy of Π(𝔸 1)\Pi(\mathbb{A}^1).

Example

The standard unit intervals [0,1][0,1] \hookrightarrow \mathbb{R} \in TopMfd \hookrightarrow ETop∞Grpd and [0,1][0,1] \hookrightarrow \mathbb{R} \in SmthMfd \hookrightarrow Smooth∞Grpd satisfy the assumptions of prop. 1.

Remark

The II of prop. 1 is in general not an interval type, but only its image Π(I)\Pi(I) is. See the discussion Geometric spaces and their cohesive homotopy types at cohesive homotopy type theory for more on this.

References

Revised on September 27, 2013 12:36:32 by Urs Schreiber (158.109.1.23)