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(1,1)-dimensional Euclidean field theories and K-theory

This is a sub-entry of geometric models for elliptic cohomology and A Survey of Elliptic Cohomology

See there for background and context.

This entry here indicates how 1-dimensional FQFTs (the superparticle) may be related to topological K-theory.

raw material: this are notes taken more or less verbatim in a seminar – needs polishing

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(1,1)d EFTs

recall the commercial for supergeometry with which we ended last time: the grading introduced by supergeometry makes it possible to have push-forward diagrams of the kind:

(01)TFTs n(X)/ H dR n(X) (01)TFT 0(X)/ H dR 0(pt)\array{ (0|1)TFTs^n(X)/\simeq &\leftarrow& H^n_{dR}(X) \\ \downarrow && \downarrow \\ (0|1)TFT^0(X)/\simeq &\leftarrow& H^0_{dR}(pt) }

Example of 1-EFT

σ 1(M n)=E:1EBtV\sigma_1(M^n) = E : 1-EB \to tV
ptΓMpt \mapsto \Gamma M
(pt[0,t])e tΔ(pt \stackrel{[0,t]}{\to}) \mapsto e^{- t \Delta}

Example of (11)EFT associated to a spin manifold, there is the spinor bundle

S=S +S S = S^+ \oplus S^-

a /2-graded vector bundle and on this there is the Dirac operator

D:Γ(S)Γ(S)D : \Gamma(S) \to \Gamma(S)

where Γ(S)=Γ(S +)Γ(S ). So we can write

D=(0 D D+ 0)D = \left( \array{ 0 & D_- \\ D+ & 0 } \right)
σ 11(M):Bord 11TV\sigma_{1|1}(M) : Bord_{1|1} \to TV
01E( 01)=Γ(S)\mathbb{R}^{0|1} \mapsto E(\mathbb{R}^{0|1}) = \Gamma(S)

there is an involution invol: 01 01. It maps to

involgradinginvolutioninvol \mapsto grading involution

we have the following moduli space of super intervals (super 1d-bordisms)

+ 11{superintervalsI t,θ}/\mathbb{R}^{1|1}_+ \simeq \{super intervals I_{t,\theta}\}/\sim

and these are mapped by the EFT as

I t,θe tD 2+θDI_{t,\theta} \mapsto e^{-t D^2 + \theta D}

(here we are implicitly working in the topos of sheaves on the category of supermanifolds and these equations have to be interpreted in that topos-logic, mapping generalized elements to generalized elements).

So we have for E a 11 EFT a reduced non-susy field theory

(11)EBord E TV E red EBord 1 spin\array{ (1|1)EBord &\stackrel{E}{\to}& TV \\ \uparrow & \nearrow_{E_{red}} \\ EBord_1^{spin} }

Definition E(11)EFT, the partition function Z E of E is the function

Z E: +Z_E : \mathbb{R}_+ \to \mathbb{C}
tZ E red(t)=E red(S t 1)t \mapsto Z_{E_{red}}(t) = E_{red}(S^1_t)

that sends a length to the value of the EFT on the circle of that circumferene.

Example Consider from above the EFT

E=σ 11(M)E = \sigma_{1|1}(M)

look at its reduced part

z E(t)=E red(S t 1)z_E(t) = E_{red}(S^1_t)

notice that by the above this assigns

[0,t]E rede tD 2[0,t] \stackrel{E_{red}}{\mapsto} e^{-t D^2}
S t 1str(e tD 2)=tr(e tD 2) eventr(e tD 2) oddS^1_t \mapsto str(e^{-t D^2}) = tr(e^{-t D^2})|_{even} - tr(e^{-t D^2})|_{odd}

where on the right we have the super trace?.

This evaluates to

str(e tD 2)= λSpec(D 2)e tλsdimE λstr(e^{-t D^2}) = \sum_{\lambda \in Spec(D^2)} e^{-t \lambda} sdim E_{\lambda}

where the super dimension? of the eigenspace? E λ is

dimE λ +dimE λ dim E^+_\lambda - dim E^-_\lambda

and this vanishes for λ0 since there D:E λ +E λ

is an isomorphism.

So further in the computation we have

=dimkerD +dimcokerD +=A^(M)\cdots = dim ker D_+ - dim coker D_+ = \hat A(M)

where the last step is the Atiyah-Singer index theorem.

So due to supersymmetry , the partition function has two very special properties:

  • it is constant – in that it does not depend on t,

  • it takes integer values .

recall from VX a vector bundle with connection we get a 1d EFT

E (V,)1dEFT(X)E_{(V,\nabla)} \in 1d EFT(X)

given by the assignment

E (V,):1sEB(X)TVE_{(V,\nabla)} : 1s EB(X) \to TV
(x:ptX)V x=fiberofVoverx(x : pt \to X) \mapsto V_x = fiber of V over x

a morphism is an interval [0,t] of length t equipped with a map γ:[0,t]X, this is sent to the parallel transport associated with the connection on a bundle

γ(V γ xV γ y)\gamma \mapsto (V_{\gamma_x} \to V_{\gamma_y})

Now refine this example to super-dimension (11):

example of a (11)-EFT over X consider

EBord (11)EBord 1(X)E (V,)TVEBord_{(1|1)} \to EBord_{1}(X) \stackrel{E_{(V,\nabla)}}{\to} TV

given by the assignment

(Σ (11)X)((Σ red (11)X)paralleltransportasbefore(\Sigma^{(1|1)} \to X)( \mapsto (\Sigma^{(1|1)}_{red} \to X) \mapsto parallel transport as before

so we just forget the super-part and consider the same parallel transport as before.

now to K-theory:

KO 0(X)= Grothendieck group of real vector bundles over X

KO n(pt)={ n=0mod4 2 n=1,2mod8 0 otherwiseKO^{-n}(pt) = \left\{ \array{ \mathbb{Z} & n = 0 mod 4 \\ \mathbb{Z}_2 & n = 1,2 mod 8 \\ 0 & otherwise } \right.

there is a Bott element βKO 8(pt)

such that

KO *(pt) [u,u 1]KO^*(pt) \stackrel{\simeq_{\mathbb{Q}}}{\to} \mathbb{Z}[u,u^{-1}]
βu 2\beta \mapsto u^2

now the push-forward in topological K-theory

p:X nptp : X^n \to pt

for X a closed spin structure manifold

then there exists an embedding XS n+m. Let ν be the normal bundle to this embedding.

then we define

X:KO k(X)KO kn(pt)\int_X : KO^k(X) \to KO^{k-n}(pt)

as follows:

let D(ν) be the disk bundle? and S(ν) be the sphere bundle? of ν. Then the Thom bundle? is

T(ν):=D(ν)/S(ν)T(\nu) := D(\nu)/S(\nu)

we get a map

S n+mCT(ν):=D(ν)/S(ν)S^{n+m} \stackrel{C}{\to} T(\nu) := D(\nu)/S(\nu)

involving the Thom isomorphism

C(X)={X ifxD(ν) * otherwiseC(X) = \left\{ \array{ X & if x \in D(\nu) \\ * & otherwise } \right.

then we set

KO k(X) X KO kn(pt) Thomiso suspension KO˜ k+m(T(ν)) C * \array{ KO^k(X) && \stackrel{\int_X}{\to}&& KO^{k-n}(pt) \\ & {}_{Thom iso}\searrow &&& \downarrow^{\simeq}_{suspension} \\ && \tilde KO^{k+m}(T(\nu)) &\stackrel{C^*}{\to}& }

now start with X n again a spin manifold

then

theorem (Stolz-Teichner): we have the horizontal isomorphism in the following diagram:

[E (V,)] [V +V ] 1 (11)EFT 0(X)/ conc KO 0(X) 1 quantization X σ (11)(X) EFT n(pt)/ conc KO n α(X) partitionfunc Atiyahsαinvariant ([u,u 1]) n indexD=A^(X)u n/4\array{ && [E_{(V,\nabla)}]&& \stackrel{}{\leftarrow} && [V^+ - V^-] \\ 1 \in &&(1|1)EFT^0(X)/_{conc} &&\stackrel{\simeq}{\to}&& KO^0(X) && \ni 1 \\ \downarrow &&\downarrow^{quantization} &&&& \downarrow^{\int_X} && \downarrow \\ \sigma_{(1|1)}(X) &&EFT^{-n}(pt)/_{conc} &&\stackrel{\simeq}{\to}&& KO^{-n} && \alpha(X) \\ &\searrow&&{}_{partition func}\searrow&& \swarrow_{\simeq} && \swarrow_{Atiyah's \alpha invariant} \\ &&&& (\mathbb{Z}[u,u^{-1}])^{-n} \\ &&&& index D = \hat A(X) u^{n/4} }

question if we don’t divide out concordance, do we get differential K-theory on the right?

answer presumeably, but not worked out yet

References

  • Stefan Stolz (notes by Arlo Caine), Supersymmetric Euclidean field theories and generalized cohomology Lecture notes (2009) (pdf)