unitalization

The *unitalization of a non-unital algebra is a unital algebra with a unit freely adjoined.*

For $R$ a commutative ring write $R Alg_{\mathrm{u}}$ for the category of nonassociative algebras with unit over $R$ and unit-preserving homomorphisms, and write $R Alg_{\mathrm{nu}}$ for nonunital nonassociative $R$-algebras. Note that $R Alg_{\mathrm{u}}$ is a subcategory of $R Alg_{\mathrm{nu}}$, as we use both ‘non-unital’ and ‘non-associative’ in accordance with the red herring principle.

The inclusion functor $U\colon R Alg_{\mathrm{u}} \to R Alg_{\mathrm{nu}}$ has a left adjoint $(-)^+\colon R Alg_{\mathrm{u}} \to R Alg{\mathrm{u}}$. For $A \in R Alg_{\mathrm{nu}}$ we say $A^+$ is the **unitalization** of $A$.

Explicitly, $A^+ = A \oplus R$ as an $R$-module, with product given by

$(a_1, 0) (a_2, 0) = (a_1 a_2, 0) ,$

$(0, r_1) (0, r_2) = (0, r_1 r_2) ,$

$(a,0) (0,r) = (0,r) (a,0) = (r a, 0) ,$

or in general

$(a_1, r_1) (a_2, r_2) = (a_1 a_2 + r_2 a_1 + r_1 a_2, r_1 r_2) .$

We often write $(a, r)$ as $a + r$ or $a \oplus r$, which makes the above formulas obvious.

If $A$ is an associative algebra, then $A^+$ will also be associative; if $A$ is a commutative algebra, then $A^+$ will also be commutative.

Revised on January 14, 2012 07:08:55
by MTS?
(184.187.181.145)