# nLab topological concrete category

Topological categories

category theory

# Topological categories

## Warning

The term ‘topological category’ is traditional, and comes from the frequent examples in topology. It does not mean an internal category or enriched category in Top (a topologically enriched category)! (Fortunately the term topological groupoid is not taken by this tradition; indeed, the only groupoid that is a topological category over $Set$ is trivial. On the other hand, there is use of the term ‘topological functor’, which we tend to avoid other than below.)

## Idea

A topological category is a concrete category with nice features matching the ability to form weak and strong topologies in Top.

## Definition

### Default version

Most generally, the definition relates to a functor $U\colon C \to D$ (such as the forgetful functor from $Top$ to Set), but one can think of this as giving $C$ as a bundle over $D$. Sometimes, when $D$ is in fact Set, the category $C$ satisfying the properties described belows is called a topological construct (Preuss). Usually $C$ and $D$ will be large categories.

By a space we will mean an object of $C$, and by an algebra we will mean an object of $D$. By a map we will mean a morphism in $C$, and by a homomorphism we will mean a morphism in $D$. (The reason is that, typically, $C$ will be a category of spaces with some kind of topological structure while $D$ will be, if not $Set$, then some kind of algebraic category.)

Then $C$ is a topological category over $D$ if, given any algebra $X$ and any (possibly large) family of spaces $S_i$ and homomorphisms $f_i\colon X \to U(S_i)$ (that is, a “$U$-structured” source from $X$), there exists an initial lift (think: “smallest topology rendering the $f_i$ continuous”), which is to say

• a space $T$ such that $U(T)=X$, and maps $m_i\colon T \to S_i$ such that $U(m_i) = f_i$, and

• given any space $T'$, homomorphism $g'\colon U(T') \to X$, and maps $m'_i\colon T' \to S_i$, if each composite $g' ; f_i$ equals $U(m'_i)$, then there exists a unique map $n\colon T' \to T$ such that $U(n) = g'$ and $n ; m_i = m'_i$.

Here are some illustrative commutative diagrams (if you can read them):

$\array { T' \\ n \downarrow \downarrow n' & \searrow^{m'_i} \\ T & \underset{m_i}\rightarrow & S_i } \;\;\; \stackrel{U}\mapsto \;\;\; \array { U(T') \\ U(n) \downarrow \downarrow U(n') & \searrow^{g'} & & \searrow^{U(m'_i)} \\ U(T) & = & X & \underset{f_i}\rightarrow & U(S_i) \\ & & \underset{U(m_i)}\longrightarrow }$

It follows by a clever argument that $U\colon C \to D$ must be faithful; see Theorem 21.3 of ACC. That is also often included in the definition, in which case the uniqueness of $n$ can be left out. Thus we may think of objects of $C$ as objects of $D$ equipped with extra structure. The idea is then that $T$ is $X$ equipped with the initial structure or weak structure determined by the requirement that the homomorphisms $f_i$ be structure-preserving maps.

The dual concept could be called a cotopological category. However, this is not actually anything new; $U\colon C \to D$ is topological if and only if $U^op\colon C^op \to D^op$ is. This is a categorification of the theorem that any complete semilattice is a complete lattice. Thus, every topological category also has final (not usually called terminal) or strong structures, each determined by a family of homomorphisms $f_i\colon U(S_i) \to X$ (a $U$-structured sink to $X$).

Both of these results (faithfulness and self-duality) depend on the fact that we have allowed the family $\{S_i\}$ to be potentially large. Counterexamples are easy to find. For instance, if $C$ is a large category with all (small) products, then the functor $C \to 1$ to the terminal category satisfies the above lifting property for small families $\{S_i\}$. However, it need not satisfy the dual property (unless $C$ also has all small coproducts) nor need it be faithful.

It also follows that $U$ is a Grothendieck fibration and opfibration.

### Amnestic version

Since initial lifts have a universal property, they are unique up to unique isomorphism. However, it is traditional in some literature to ask that they be literally unique (this is done for instance in ACC). This is tantamount to deciding that $U$ should be an amnestic functor. A drawback (from an nPOV) is that this condition violates the principle of equivalence, and arguably doesn’t add anything mathematically important.

Thus, although it occurs in the literature, here we will consider it purely optional. (It is possible that some results recorded here about topological categories will depend on this assumption, but only ‘evil’ results could be affected.)

### Weak version

On the other hand, the default definition above does already refer to equality of objects in the condition $U(T)=X$; thus as stated it already violates the principle of equivalence, just as the notion of Grothendieck fibration does. But (also as for Grothendieck fibrations) this other use of equality of objects is really more of a “typing judgment”, which can be made precise by working with displayed categories instead. (In the context of homotopy type theory, the amnestic condition is equivalent to “fiberwise univalence”.)

However, if we want to, we can also formulate a “fully isomorphism-invariant” version of the definition, corresponding to the weakened bicategorical notion of Street fibration. In this case, an initial lift consists of:

• a space $T$, an isomorphism $g\colon U(T) \to X$, and maps $m_i\colon T \to S_i$ such that each composite $g ; f_i$ equals $U(m_i)$ and,

• given any space $T'$, homomorphism $g'\colon U(T') \to X$, and maps $m'_i\colon T' \to S_i$, if each composite $g' ; f_i$ equals $U(m'_i)$, then there exists a unique map $n\colon T' \to T$ such that $U(n) ; g = g'$ and $n ; m_i = m'_i$.

$\array { T' \\ n \downarrow \downarrow n' & \searrow^{m'_i} \\ T & \underset{m_i}\rightarrow & S_i } \;\;\; \stackrel{U}\mapsto \;\;\; \array { U(T') \\ U(n) \downarrow \downarrow U(n') & \searrow^{g'} & & \searrow^{U(m'_i)} \\ U(T) & \overset{\sim}\underset{g}\rightarrow & X & \underset{f_i}\rightarrow & U(S_i) \\ & & \underset{U(m_i)}\longrightarrow }$

## Further properties

• If $C$ is topological over $D$, then so is any full retract of $C$, as long as the functors involved live in $Cat/D$.

• In particular, a reflective or coreflective subcategory of $C$ is topological, as long as the reflectors or coreflectors become identity morphisms in $D$.

• The forgetful functor $U\colon C \to D$ is not only faithful but also (for different reasons) essentially surjective. Thus it is never full (except in the trivial case where $U$ is an equivalence, of course).

• If $D$ is complete or cocomplete, then so is $C$.

• If $D$ is total or cototal, then so is $C$; see solid functor.

• If $D$ is mono-complete or epi-cocomplete, then so is $C$.

• If $D$ is well-powered or co-well-powered, then so is $C$.

• If $D$ has a factorization structure for sinks $(E,M)$, then $C$ has one $(E',M')$, where $M'$ is the collection of morphisms in $C$ lying over $M$-morphisms in $D$, and $E'$ the collection of final sinks in $C$ lying over $E$-sinks in $D$. This generalizes the lifting of orthogonal factorization systems along Grothendieck fibrations.

• If $D$ is concrete, then so is $C$. More generally, if $D$ has a generator, then $C$ is concrete over $D$.

• In particular, if $D$ is Set, then $C$ is a concrete category that is complete, cocomplete, well powered, and well copowered.

## Functors

• A functor $F\colon C\to C'$ between topological concrete categories $C/D$, $C'/D$ with the same base category $D$ preserves initial lifts iff it is right adjoint. It preserves final lifts iff it is left adjoint.

• More generally: If a functor $F\colon C\to C'$ between topological concrete categories $C/D$, $C'/D'$ with different base categories lying over a functor $F_0: D\to D'$. If $F$ is right (left) adjoint, then $F_0$ is right (left) adjoint and $F$ preserves initial (final) lifts. A partial converse holds: If $F_0$ is right (left) adjoint to $G_0$ and $F$ preserves initial (final) lifts, then there is functor $G$ lying over $G_0$ so that $F$ is right (left) adjoint to $G_0$.

## Special cases

• If $X$ is any algebra, then there is a discrete space over $X$ induced by the empty family of maps. Similarly, we have an indiscrete space with the final structure induced by no maps. This defines functors $disc, indisc\colon D \to C$ that are respectively left and right adjoints of $U$.

• Suppose that $D$ has an initial object $0_D$. Then the discrete space $0_C$ over $0_D$ is initial in $C$. Similarly, the indiscrete space over a terminal object in $D$ is terminal in $C$.

• More generally, suppose that $D$ has products or coproducts (indexed by whichever cardinalities you may wish to consider). Then $C$ also has (co)products, lying over the (co)products in $D$, with structures induced by the product projections or coproduct inclusions.

• More general limits and colimits are constructed in a similar way. However, it is not typically the case that $U$ creates (co)limits in $C$ because creation of a limit requires that every preimage of the limiting cone is limiting. This fails for $U: \mathrm{Top} \to \mathrm{Set}$ since we can coarsen the topology on the limit vertex to obtain a counterexample.

• If a single algebra $X$ has been given the structure of several spaces, then there are a supremum structure and an infimum structure on $X$ induced (as the initial and final structures) by the various incarnations of its identity homomorphism. Exploiting this shows how to construct final structures out of initial ones and conversely.

• If $X$ is a regular subalgebra of some $U(S)$, then the inclusion homomorphism makes $X$ into a subspace of $S$, which is also a subobject in $C$. Every regular subobject of $S$ is of this form; note however that there may be nonregular subobjects in $C$ even if all subobjects in $D$ are regular.

## Familiarly fibrations

The theory of topological functors can be developed along the lines of Grothendieck’s theory of fibrations, where cartesian morphisms are replaced by cartesian families. In this way just as by definition “A functor is a fibration if it creates cartesian morphisms and cartesian morphism compose”, there is the definition “A functor is topological if it creates cartesian families and cartesian families compose”.

• Jiří Adámek, Horst Herrlich, & George E. Strecker; 1990; Abstract and Concrete Categories; originally published John Wiley & Sons ISBN 0-471-60922-6; free on-line edition (4.2MB PDF).
• Gerhard Preuss; 2002; Foundations of Topology: An Approach to Convenient Topology; Kluwer ISBN 1-4020-0891-0.