# Homotopy Type Theory an axiomatization of the real numbers > history (Rev #7, changes)

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## Definition

### Commutative $\mathbb{Q}$-algebras

A Every commutative ring$R$ is has a commutative ring homomorphism \mathbb{Q} h:\mathbb{Z} \to R -algebra if from there the is integers a to commutative ring homomorphism h:\mathbb{Q} \to R . , and there is an injection$i:\mathbb{Z}_+ \to \mathbb{Z}$ from the positive integers to the integers.

A commutative ring $R$ is a commutative $\mathbb{Q}$-algebra if there is a function $j:\mathbb{Z}_+ \to R$ such that for all positive integers $a:\mathbb{Z}_+$, $h(i(a)) \cdot j(a) = 1$.

### Totally ordered commutative rings

A commutative ring $R$ is a totally ordered commutative ring if it comes with a function $\max:R \times R \to R$ such that

• for all elements $a:R$, $\max(a, a) = a$

• for all elements $a:R$ and $b:R$, $\max(a, b) = \max(b, a)$

• for all elements $a:R$, $b:R$, and $c:R$, $\max(a, \max(b, c)) = \max(\max(a, b), c)$

• for all elements $a:R$ and $b:R$, $\max(a, b) = b$ implies that for all elements $c:R$, $\max(a + c, b + c) = b + c$

• for all elements $a:R$ and $b:R$, $\max(a, 0) = a$ and $\max(b, 0) = b$ implies $\max(a \cdot b, 0) = a \cdot b$

• for all elements $a:R$ and $b:R$, $\max(a, b) = a$ or $\max(a, b) = b$

### Totally ordered commutative $\mathbb{Q}$-algebras

Given totally ordered commutative rings $R$ and $S$, a commutative ring homomorphism $h:R \to S$ is monotonic if for all $a:R$ and $b:R$, $\max(h(a), h(b)) = h(\max(a, b))$.

A Every totally ordered commutative ring$R$ is has a totally monotonic ordered commutative ring homomorphism \mathbb{Q} h:\mathbb{Z} \to R -algebra if from there the is integers a to monotonic commutative ring homomorphism h:\mathbb{Q} \to R . , and there is an monotonic injection$i:\mathbb{Z}_+ \to \mathbb{Z}$ from the positive integers to the integers.

A totally ordered commutative ring $R$ is a totally ordered commutative $\mathbb{Q}$-algebra if there is a function $j:\mathbb{Z}_+ \to R$ such that for all positive integers $a:\mathbb{Z}_+$, $h(i(a)) \cdot j(a) = 1$.

### Strictly ordered integral ring

A totally ordered commutative ring $R$ is a strictly ordered integral ring if it comes with a type family $\lt$ such that

• for all elements $a:R$ and $b:R$, $a \lt b$ is a proposition
• for all elements $a:R$, $a \lt a$ is false
• for all elements $a:R$, $b:R$, and $c:R$, if $a \lt c$, then $a \lt b$ or $b \lt c$
• for all elements $a:R$ and $b:R$, if $a \lt b$ is false and $b \lt a$ is false, then $a = b$
• for all elements $a:R$ and $b:R$, if $a \lt b$, then $b \lt a$ is false.
• $0 \lt 1$
• for all elements $a:R$ and $b:R$, if $0 \lt a$ and $0 \lt b$, then $0 \lt a + b$
• for all elements $a:R$ and $b:R$, if $0 \lt a$ and $0 \lt b$, then $0 \lt a \cdot b$
• for all elements $a:R$ and $b:R$, if $0 \lt \max(a, -a)$ and $0 \lt \max(b, -b)$, then $0 \lt \max(a \cdot b, -a \cdot b)$

### Strictly ordered integral $\mathbb{Q}$-algebras

Given strictly ordered integral rings $R$ and $S$, a monotonic commutative ring homomorphism $h:R \to S$ is strictly monotonic if for all $a:R$ and $b:R$, $a \lt b$ implies $h(a) \lt h(b)$.

A Every strictly ordered integral ring$R$ is has a strictly ordered monotonic integral commutative ring homomorphism \mathbb{Q} h:\mathbb{Z} \to R -algebra if from there the is integers a to strictly monotonic commutative ring homomorphism h:\mathbb{Q} \to R . , and there is an strictly monotonic injection$i:\mathbb{Z}_+ \to \mathbb{Z}$ from the positive integers to the integers.

### Archimedean ordered integral $\mathbb{Q}$-algebras

A strictly ordered integral ring $R$ is a strictly ordered integral $\mathbb{Q}$-algebra if there is a function $j:\mathbb{Z}_+ \to R$ such that for all positive integers $a:\mathbb{Z}_+$, $h(i(a)) \cdot j(a) = 1$.

A strictly ordered integral $\mathbb{Q}$-algebra $A$ is an Archimedean ordered integral $\mathbb{Q}$-algebra if for all elements $a:A$ and $b:A$, if $a \lt b$, then there merely exists a rational number $q:\mathbb{Q}$ such that $a \lt h(q)$ and $h(q) \lt b$.

### Sequentially Cauchy complete Archimedean ordered integral $\mathbb{Q}$-algebra

A strictly ordered integral $\mathbb{Q}$-algebra $A$ is an Archimedean ordered integral $\mathbb{Q}$-algebra if for all elements $a:A$ and $b:A$, if $a \lt b$, then there merely exists a rational number $q:\mathbb{Q}$ such that $a \lt h(q)$ and $h(q) \lt b$.

Let $A$ be an Archimedean ordered integral $\mathbb{Q}$-algebra and let

### Sequentially Cauchy complete Archimedean ordered integral $\mathbb{Q}$-algebras

$A_{+} \coloneqq \sum_{a:A} 0 \lt a$

Let $A$ be an Archimedean ordered integral $\mathbb{Q}$-algebra and let

be the positive elements in $A$. $A$ is sequentially Cauchy complete if every Cauchy sequence in $A$ converges:

$A_{+} \coloneqq \sum_{a:A} 0 \lt a$
$isCauchy(x) \coloneqq \forall \epsilon \in A_{+}. \exists N \in I. \forall i \in I. \forall j \in I. (i \geq N) \wedge (j \geq N) \wedge (\vert x_i - x_j \vert \lt \epsilon)$

be the positive elements in $A$. $A$ is sequentially Cauchy complete if every Cauchy sequence in $A$ converges:

$isLimit(x, l) \coloneqq \forall \epsilon \in A_{+}. \exists N \in I. \forall i \in I. (i \geq N) \to (\vert x_i - l \vert \lt \epsilon)$
 \forall x: \mathbb{N} \to A. isCauchy(x) \wedge \coloneqq \forall \epsilon \in A_{+}. \exists l N \in A. I. isLimit(x, \forall l) i \in I. \forall j \in I. (i \geq N) \wedge (j \geq N) \wedge (\vert x_i - x_j \vert \lt \epsilon)
$isLimit(x, l) \coloneqq \forall \epsilon \in A_{+}. \exists N \in I. \forall i \in I. (i \geq N) \to (\vert x_i - l \vert \lt \epsilon)$
$\forall x: \mathbb{N} \to A. isCauchy(x) \wedge \exists l \in A. isLimit(x, l)$

Revision on June 17, 2022 at 08:46:20 by Anonymous?. See the history of this page for a list of all contributions to it.