nLab
Puiseux series

Contents

Definition

Let K be a field. A Puiseux series with coefficients in K is a formal Laurent series

f(t)= kma kt k/r(1)f(t) = \sum_{k \geq m} a_k t^{k/r} \qquad (1)

where r is a positive integer, m is an integer, and each a k belongs to K. Somewhat more abstractly but also more meaningfully, if is the poset of positive integers ordered by divisibility (so that 1 is the least element), then the field of Puiseux series is the filtered colimit of the diagram of fields

F: FieldF: \mathbb{N}_{\cdot} \to Field

where each F(n) is the field of Laurent series K((t)), but where F(m)F(n) (in case mn) is the field homomorphism taking f(t) to f(t n/m).

The field of Puiseux series carries a valuation whose values are in the ordered group of rationals (,+): for f(t) as in (1), v(f) is the least exponent k/r for which a k0.

Puiseux-Newton expansions

Puiseux series were in essence considered by Isaac Newton, who developed a method of expanding algebraic functions as Puiseux series, based on an analogue of Newton's method of approximating roots. Here is a sample theorem:

Theorem

If K is algebraically closed and has characteristic 0, then the field of Puiseux series over K is the algebraic closure of the field of Laurent series over K.

Proof (sketch)

It is enough to show that every degree n extension E of the field of Laurent series K((x)) is of the form K((x 1/n)). For this, it suffices that the integral closure B of K[[x]] in E be of the form K[[x 1/n]].

Generally speaking, let A be a complete DVR (discrete valuation ring) with maximal ideal 𝔪 A and residue class field k A, and let F be its field of fractions. Let E be a degree n extension of F, and let B be the integral closure of A in E. Then B is also a complete DVR. We may write the ideal 𝔪 AB of B as 𝔪 B e where e is the ramification index, and we have

n=deg FE=rank AB=rank A/𝔪 AB/𝔪 AB=dim k AB/𝔪 B e=edim k Ak Bn = deg_F E = rank_A B = rank_{A/\mathfrak{m}_A} B/\mathfrak{m}_A B = dim_{k_A} B/\mathfrak{m}_B^e = e \cdot dim_{k_A} k_B

where the last equation holds because 𝔪 B i/𝔪 B i+1k B as k B-modules and therefore also as k A-modules. In the case A=K[[x]] where k A=K, we have that dim k Ak B=1 since K is algebraically closed, and therefore e=n. In other words, (x)B=𝔪 B n, so we can write x=uπ n where π generates the maximal ideal of B and u is a unit of B.

The residue class u¯K has an n th root (again by algebraic closure); in fact a simple root since char(K)=0. By Hensel's lemma?, this lifts to an n th root of u in B. The element u 1/nπ is thus an n th root of x, and is a generator of the maximal ideal of B. Writing this element as y=x 1/n, the ring K[[y]]=A[x 1/n]B is an A-submodule of full rank n and integrally closed (being abstractly isomorphic to A, which is integrally closed because it’s a principal ideal domain and therefore a unique factorization domain), so that K[[y]]=B, as was to be shown.

Example

(Intend to solve for y in y 3xy+1=0 as a Puiseux series in x.)

References

The sketched proof of theorem 1 was extracted from notes on a seminar by Boyarchenko on local class field theory:

  • Mitya Boyarchenko, Kottwitz Seminar Lectures, (U. Michigan, Winter 2011). (pdf)

and the reader may refer to the classic text by Serre for a fuller treatment:

  • Jean-Pierre Serre, Local Fields (trans. Marvin J. Greenberg), Graduate Texts in Math. 67, Springer 1980.

For a noncommutative generalization see

  • D. Grigoriev, Analogue of Newton-Puiseux series for non-holonomic D-modules and factoring, Moscow Math. J. 9, 2009, 775–800, pdf; MPIM2008-6, pdf

Other references

  • Jan Kiwi, Puiseux series dynamics of Quadratic rational maps, arxiv/1106.0059

(Proof or suitable reference to be inserted later.)

Revised on February 4, 2013 21:28:02 by Todd Trimble (67.81.93.26)