Fourier transform

Let $G$ be a locally compact Hausdorff abelian topological group with invariant (= Haar) measure $\mu$. Then for each $f\in L_1(G,\mu)$, define its **Fourier transform** $\hat{f}$ as a function on its Pontrjagin dual group $\hat{G}$ given by

$\hat{f}(\chi) = \int_G f(x) \widebar{\chi(x)} d\mu(x),\,\,\,\chi\in\hat{G}.$

The Fourier transform of $f\in L_1(G,\mu)$ is always continuous and bounded on $\hat{G}$; the transform of the convolution of two functions is the product of the transforms of each of the functions separately.

In the classical case of **Fourier series**, where $G=\mathbb{Z}$ (the additive group of integers) and $\hat{G}=S^1$ (the circle group), the Fourier transform restricts to a unitary operator between the Hilbert spaces $L_2(S^1,d t)$ and $l_2(\mathbb{Z})$ and the Fourier coefficients are the numbers

$c_n := \hat{f}(\chi_n) = \int_0^1 f(t) e^{-2\pi i n t} d t,$

for $n\in\mathbb{Z}$, where the functions $\chi_n(t)= e^{2\pi i n t}$ form an orthonormal basis of $L_2(S^1,d t)$. The Fourier transform $\hat{\chi_n}$ is then viewed as the $\mathbb{Z}$-series $\delta_n$ which in the $n$-th place has $1$ and elsewhere $0$. The Fourier transform replaces the operator of differentiation $d/d t$ by the operator of multiplication by the series $\{2\pi i n\}_{n\in\mathbb{Z}}$.

In general, if $G$ is a compact abelian group (whose Pontrjagin dual is discrete), one can normalize the invariant measure by $\mu(G)=1$ and $\hat{\mu}(X)=card(X)$ for $X\subset\hat{G}$. Then the Fourier transform restricts to a unitary operator from $L_2(X,\mu)$ to $L_2(\hat{G},\hat{\mu})$.

A Fourier transform of a function on the real line $\mathbb{R}$ is called its **Fourier integral**:

$\hat{f}(\lambda)=\int_{-\infty}^\infty f(x) e^{-2\pi i\lambda x} d x.$

It is usually defined as a linear automorphism of the Schwarz space? $S(\mathbb{R})\to S(\mathbb{R})$; there is also an appropriate extension to the space of distributions $S'(\mathbb{R})$ by $\langle \hat{f},\phi\rangle := \langle f, \hat{\phi}\rangle$ where $f\in S'(\mathbb{R})$ and $\phi\in S(\mathbb{R})$. The Fourier transform and the inverse Fourier transform are continuous, mutually inverse operators $S'(\mathbb{R})\to S'(\mathbb{R})$. There is also a unitary operator on $L_2(\mathbb{R},d x)$ which when restricted to $L_2(\mathbb{R},d x)\cap L_1(\mathbb{R},dx)$ agrees with the Fourier transform.

The study of the Fourier transform is the main subject of Fourier analysis and, together with its generalizations like wavelet transform, of harmonic analysis. Regarding that, with an appropriate choice of functional spaces, the Fourier transform has an inverse, each function can be represented as a Fourier inverse of some function, which amounts to a decomposition into an integral over a Haar measure along some basis. Thus the function gets *analysed* into *harmomics*.

For noncommutative topological groups, instead of continuous characters one should consider irreducible unitary representations, which makes the subject much more difficult. There are also generalizations in noncommutative geometry, see quantum group Fourier transform.

- Gerald B. Folland,
*A course in abstract harmonic analysis*, Studies in Advanced Mathematics. CRC Press, Boca Raton, FL, 1995. x+276 pp. gBooks

category: analysis

Revised on August 27, 2014 10:41:30
by Urs Schreiber
(82.136.246.44)